JML ELECTRONICS STUDY Lab#1:  Ex#3.     push "play"  

   Total resistance, Rt, in a series-parallel curcuit is (Rs X Ri / Rs + Ri).    Find the total current. Plug in these values  R1,R2,& R3=3,  R4,R5, & R6=4,  R7, R8, & R9=5 ...then, plug in  R1=10,  R2=5,   R3=5 R1= R2= R3= R4= R5= R6= R7= R8= R9=!!

Rs = R1 + R2 + R3 = ohms.( black section resistance) Rt1 = (R4 x Rs)/(R4 + Rs) =(x)/(+) = ohms

Now place Rt1 in the textbox below and hit the calculate2 button.
Rt1= Rg = R6 + R7 + Rt1 = ohms.(green branch resistance) Rt2 = (R5 x Rg)/(R5 + Rg) = (x)/(+) = ohms
Rt = R8 + R9 + Rt2 = ohms.(blue branch resistance)
It = 12volts / Rt = amps
I5 = amps

(Answer: Total current =.9241)
Now try R1,R2,R3=3 : R4,R5,R6 = 1 : R7,R8,R9 =2 What happenned to the Total current? Which resistors are the hottest? Try R1-R9 = 5. What happens to the currents?. Try just changing R1-R9 =1. I = total current really gets huge. Notice that the current the branches with the most resistance had to lowest currents because the voltage and current for a resistor are indirectly proportional to eachother. so when one goes up the other one goes down and vice versa.
When you finish tryings all 5 sets of Rs send an email to zjev06@gmail.com.
Give a summary of the results of each and tell me what you have learned.

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