JML ELECTRONICS STUDY Lab#2                  
1.    Previous curcuits were DC (direct currents), this is an example of an AC alternating
current curcuit. In this curcuit we have a coil and a capacitor. Reactance is the
resistive component of a curcuit element.
  
inductive reactance                                               capacitive reactance

Ex:1     Try R1=30   R2=5   L=.106   C=220
 R1 = ohms.       R2 = ohms.       L = henries.       C = microfarads.

 
XL = (6.28)*60*L = ohms.     XC = 159000/(C*60) = ohms.    
Za = ohms.     Zb = ohms.
I1=650v/Za=amps   I2=650v/Zb=amps    IT = sqrt((ITx)**2+(ITy)**2)=amps   
For better explanation of above formula, click homework button!
ZT=650/IT=ohms.

Ex:2     Try R1=3   R2=3   L=3   C=3
Ex:3     Try R1=0   R2=0   L=3   C=3
Did you notice no change in Ex:2 and Ex:3? Why?
Ex:4     Try R1=0   R2=0   L=.106   C=220
When you finish tryings all 4 sets of Rs send an email to zjev06@gmail.com.
Give a summary of the results of each and tell me what you have learned.
 
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